General Case of the line inclined to both HP & VP.
General Case of the line inclined to both HP & VP.
( BASED ON 10 PARAMETERS )
PROBLEM 1:
Line AB is 75 mm long and it is 30. & 40. inclined to Hp & VP respectively. End AA is 12 mm above hp and 10 mm in front of VP. Draw projections. The line is in 1st quadrant.
SOLUTION STEP:
- Draw XY line and one projector.
- Locate a, 12 mm above XY line &a 10 mm below XY line
- Take 30. angles from a, & 40. from a and mark TL i.e. 75 mm on both lines. Name those points b1, and b1 respectively.
- Join both points with a, and a resp.
- Draw horizontal lines (Locus) from both points.
- Draw horizontal component of TL a b1 from point b1 and name it 1.(the length a-1 gives the length of FV as we have seen already)
- Extend it up to locus of a' and rotating and as center locate b' as shown. join a' b' as FV.
- From b' drop a projector downward & get point b1 to join a & b
PROBLEM 2:
Line AB 75 mm long makes 45. inclination with VP, while it's FV, makes 55. End A is 10 mm above HP and 15 mm in front of VP. if the line is in 1 quadrant draw its projections and find it's an inclination with HP.
SOLUTION STEPS:-
- Draw the X-Y line.
- Draw one projector for a, & a
- Locate a, 10 mm above X-Y & TV a 15 mm below XY.
- Draw a line 45. inclined to XY from point a and cut TL 75 mm on it and name that point b1 Draw locus from point b1
- Take 55. angles from a for FV above the XY line.
- Draw a vertical line from b1 up to locus of a and name it 1. It is a horizontal component of TL& is LFV.
- Continue it to the locus of a, and rotate upward up to the line of FV and name it b, This a, b, line is FV.
- Drop a projector from b, on locus from point b1, and name intersecting point b. Line a b is Tv of line AB.
- Draw locus from b, and from a, with TL distance cut point b1,
- Join a b as TL and measure its angle at a,
It will be a true angle of line with HP.
PROBLEM 3:
FV of line AB is 50. inclined to XY and measures 55 mm long while its TV is 60. inclined to the XY line. if end A is 10 mm above Hp and 15 mm in front of VP, draw its projection, find TL, inclinations of line with HP &VP.
SOLUTION STEPS:
- Draw XY line and one projector.
- Locate a, 10 mm above XY and a 15 mm below XY line.
- Draw locus from these points.
- Draw FV 50 to XY from a, and mark b, cutting 55 mm on it.
- Similarly, draw TV 60. to XY from a & drawing projector from b, Locate point b and join a b.
- Then rotating views as shown, locate True lengths ab1 & a, b1, and their angles with HP and VP.
PROBLEM 4:
Line AB is 75 mm long. it's FV and TV measure 50 mm & 60 mm long respectively. End A is 10 mm above HP and 15 mm in front of VP. Draw projections of line AB if end B is in the First Quadrant. Find angle with HP and VP.
SOLUTION STEPS:
- Draw XY line and one projector.
- Locate a, 10 mm above XY and a 15 mm below XY line.
- Draw locus from these points.
- Cut 60 mm distance on the locus of a, & mark 1, on it as it is LTV.
- Similarly cut 50 mm on the locus of a and mark point 1 as it is LFV.
- From 1, draw a vertical line upward and from a, taking TL (75 mm) in compass, mark b1, the point on it. Join a, b1, points.
- Draw locus from b1,
- With the same steps below get b1 point and draw also locus from it.
- Now rotating one of the components l.e a-1 locate b, and join a, with it to get FV.
- Locate TV similarly and measure angles θ & Φ
PROBLEM 5:
T.V. of a 75 mm long Line CD, measures 50 mm. End C is in HP and 50 mm in front of VP. END D is 15 mm in front of VP and it is above HP. Draw projections of CD and find angles with HP and VP.
SOLUTION STEPS:
- Draw XY line and one projector.
- Locate c, on XY, and c 50 mm below the XY line.
- Draw locus from these points.
- DDraw locus of d 15 mm below XY
- Cut 50 mm & 75 mm distance on the locus of d from c and mark points d & d1 as these are TV and line CD lengths resp. & join both with c.
- From d1 draw a vertical line upward up to XY l.e. up to the locus of c, and draw an arc as shown.
- Then draw one projector from d to meet this arc in d, point & join c, d,
- Draw the locus of d, and cut 75 mm on it from c, as TL
- Measure angles θ & Φ