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Interpenetration of solids The following cases are solved. refer illustration and note the common construction for all Cylinder to cylinder 2. Sq.prism to cylinder Cone to cylinder Triangular prism to cylinder Sq.prism to sq.prism Sq.prism to sq.prism(skew position) Square prism to cone (from top ) Cylinder to cone Common solution steps One solid will be standing on HP other will penetrate horizontally. Draw three views of standing solid. name views as per the illustrations. Beginning with side view draw three views of penetrating solids also. On its S.V. mark number of points and name those (either letters or nos.) The points which are on standard generators or edges of standing solid, (In S.V.) can be marked on respective generators in FV and TV and other points from SV should be brought to TV first and then projecting upward to FV. The dark and dotted line's decision should be taken by observing the side view from its right side as shown by the arrow. Acc...

Examples On Sections And Developing Of Solid Engineering Application Of Projections Of Solid. 1 ] A pentagonal prism, 30 mm base side & 50 mm axis is standing on hp on its base whose one side is perpendicular to VP. it is cut by a section plane 45 º inclined to hp, through midpoint if axis draw FV, sec.TV & sec. side view. also draw the true shape of section and Development surface of remaining solid. Solution steps: For section views: Draw three views of standing prism. Locate sec. plane in FV as described. Project points where edges are getting cut on TV & SV as shown in the illustration. Join those points in sequence and show section lines in it. Make the remaining part of the solid dark. For True shape: Draw x 1  y 1 || to sec. plane Draw projectors on it from cut points. Mark distance of points of sectioned part from TV, on above projectors from x 1  y 1 , and join in sequence. Draw section lines in it. It is required true shape. For Development: Draw the developmen...

  The principles Of  Projections of solids. Section Of Solids. Development. Intersections. Sectioning a solid An object (here solid) is cut by some imaginary cutting plane to understand the internal details of that object. The action of cutting is called Sectioning a solid & The plane of cutting is called Section plane. Two cutting actions means section planes are recommended. Section Plane Perpendicular To Vp And Inclined To Hp. (This Is a Definition Of An Aux. Inclined Plane i.e. A.I.P.) Note:- This Section Plane Appears as a Straight Line In FV. Section Plane Perpendicular To Hp And Inclined To Vp. ( This Is a Definition Of an Aux. Vertical plane i.e. A.V.P.) Note:- This Section Plane Appears as a Straight Line In TV. Remember:- After Launching a Section Plane Either In FV or TV, The Part Towards Observer Is Assumed To Be Removed. As Far As Possible the Smaller Part  Is Assumed To Be Removed. Illustration Showing Important Terms In sectioning. Typical Section Planes ...

Introduction Of Solids Solids: To understand and remember various solids in this subject properly, Those are classified & arranged in the two major groups. Dimensional parameter of different solids:     Steps to solve problems in solids Problem is solved in three steps: Step 1: Assume solid standing on the plane with which it is making inclination. (If it is inclined to HP, Assume it standing on HP) (If it is inclined to VP, Assume it standing on VP) If standing on HP its TV will be true shape of its base or top. If standing on VP its FV will be true shape of its base or top. Begin with this view. Its other view will be a rectangle (If solid is Cylinder one of the prisms ): Its other view will be a Triangle (If solid is cone or one of the pyramids):   Draw FV & TV of that solid in standing position: Step 2: Considering solid's inclination (Axis position ) Draw its FV & TV. Step 3: In the last step, considering remaining inclinations, Draw its final FV & TV...

projections of Solids Examples Categories of illustrated problems   Problem no. 1,2,3,4            General cases of solid inclined to HP & VP Problem no. 5 & 6               Cases of cube & tetrahedron Problem no. 7                      Case of freely suspended solid with side view. Problem no. 8                      Case of Cube (with side view) Problem no. 9                      Case of true length inclination with HP & VP. Problem no. 10 & 11          Cases of composite solids. (Auxiliary plane) Problem no.  12                  Case of a frustum (auxiliary plane) 1 ] A square pyramid, 40 mm base sides, and axis 60 mm long, has a triangle face on the ground and the vertical plane containing the axis makes an angle of 45 º with the VP. Draw its projections. Take apex nearer to VP Solution steps: Triangular face on HP, means it is lying on HP: Assume it standing on HP. Its Tv will show the true shape of the base (Square) Draw square of 40 mm sides with...